1
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The constant term in the expansion of $\left(1+\frac{1}{x}\right)^{20}\left(30 x(1+x)^{29}+(1+x)^{30}\right)$ is

A

${ }^{50} \mathrm{C}_{20}+30 \cdot{ }^{50} \mathrm{C}_{29}$

B

${ }^{50} \mathrm{C}_{19}+30 \cdot{ }^{49} \mathrm{C}_{19}$

C

${ }^{50} \mathrm{C}_{20}+30 \cdot{ }^{49} \mathrm{C}_{20}$

D

${ }^{50} \mathrm{C}_{20}+30 \cdot{ }^{49} \mathrm{C}_{19}$

2
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When $|x|>3$, then coefficient of $\frac{1}{x^n}$ in the expansion of $x^{3 / 2}(3+x)^{1 / 2}$ is

A

$(-1)^n \frac{1 \cdot 3 \cdot 5 \ldots(2 n-1)}{2^n n!} 3^n$

B

$(-1)^{n+1} \frac{1 \cdot 3 \cdot 5 \ldots(2 n+1)}{2^{n+2}(n+2)!} 3^{n+2}$

C

$(-1)^{n+1} \frac{1 \cdot 3 \cdot 5 \ldots(2 n-1)}{2^n n!} 3^{n+1}$

D

$(-1)^{n+1} \frac{1 \cdot 3 \cdot 5 \ldots(2 n+1)}{2^{n+3}(n+2)!} 3^{n+1}$

3
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\frac{x^2-3}{(x+2)\left(x^2+1\right)}=\frac{A}{x+2}+\frac{B x+C}{\left(x^2+1\right)}$, then $3 A+2 B-C=$

A

$\frac{8}{5}$

B

$\frac{16}{5}$

C

$\frac{3}{5}$

D

$\frac{19}{5}$

4
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $5 \sin \theta+3 \cos \left(\theta+\frac{\pi}{3}\right)+3$ lies between $\alpha$ and $\beta$ (including $\alpha, \beta$ also), then $(\alpha-\beta)(\alpha+\beta-6)=$

A

$28-5 \sqrt{3}$

B

0

C

3

D

$28+5 \sqrt{3}$

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