1
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $A(0,0,0) B(3,4,0)$ and $C(0,12,5)$ are the vertices of a $\triangle A B C$, then the $x$-coordinate of its incentre is

A

$\frac{25}{18+7 \sqrt{2}}$

B

$\frac{25}{26}$

C

$\frac{39}{18+7 \sqrt{2}}$

D

$\frac{39}{26}$

2
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $A=(0,4,-3), B=(5,0,12)$ and $C=(7,24,0)$, then $\sqrt{B A C}=$

A

$60^{\circ}$

B

$\cos ^{-1}\left(\frac{16}{\sqrt{13}}\right)$

C

$\cos ^{-1}\left(\frac{13}{38}\right)$

D

$90^{\circ}$

3
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A plane $\pi$ is passing through the points $A(1,-2,3)$ and $B(6,4,5)$. If the plane $\pi$ is perpendicular the plane $3 x-y+z=2$, then the perpendicular distance from $(0,0,0)$ to the plane $\pi$ is

A

$\frac{63}{\sqrt{594}}$

B

$\frac{32}{\sqrt{594}}$

C

$\frac{72}{\sqrt{435}}$

D

$\frac{23}{\sqrt{135}}$

4
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \mathop {\lim }\limits_{y \to 0} \frac{\sqrt{1+\sqrt{1+y^4}}-\sqrt{2}}{y^4}= $$

A

$\frac{1}{4 \sqrt{2}}$

B

$\frac{1}{2 \sqrt{2}(1+\sqrt{2})}$

C

$\frac{1}{2 \sqrt{2}}$

D

$\frac{1}{4 \sqrt{2}(1+\sqrt{2})}$