$$ \int \frac{x^4-1}{x^2 \sqrt{x^4+x^2+1}} d x= $$
$\frac{2 \sqrt{x^4+x^2+1}}{x}+C$
$\frac{\sqrt{x^4+x^2+1}}{x}+C$
$\frac{\sqrt{x^4+x^2+1}}{2 x}+C$
$\frac{4 \sqrt{x^4+x^2+1}}{x}+C$
$$ \int \frac{(3 x-2) \tan \left(\sqrt{9 x^2-12 x+1}\right)}{\sqrt{9 x^2-12 x+1}} d x= $$
$\frac{1}{3} \sec ^2 \sqrt{9 x^2-12 x+1+C}$
$\frac{1}{3} \sec ^2 x+C$
$\frac{1}{2} \log \left|\sec \sqrt{9 x^2-12 x+1}\right|+C$
$\frac{1}{3} \log \left|\sec \sqrt{9 x^2-12 x+1}\right|+C$
$\int_{\frac{-\pi}{4}}^{\frac{\pi}{3}}\left|\tan \left(x-\frac{\pi}{6}\right)\right| d x=$
$\log \frac{\sqrt{3}-1}{\sqrt{6}}$
$\log (2 \sqrt{2}(\sqrt{3}+1))$
$\log \frac{\sqrt{3}+1}{\sqrt{6}}$
$\log (2 \sqrt{2}(\sqrt{3}-1))$
$$ \int_0^\pi \frac{x \sin x}{\sin ^2 x+2 \cos ^2 x} d x= $$
$\frac{\pi}{2}$
$\frac{\pi^2}{2}$
$\frac{\pi^2}{4}$
$\frac{\pi}{4}$
AP EAPCET Papers
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