$$ \int_0^\pi \frac{x \sin x}{\sin ^2 x+2 \cos ^2 x} d x= $$
$\frac{\pi}{2}$
$\frac{\pi^2}{2}$
$\frac{\pi^2}{4}$
$\frac{\pi}{4}$
The area of the region lying between the curves $y=\sqrt{4-x^2}, y^2=3 x$ and the $Y$-axis is
$\frac{\pi}{3}-\frac{1}{2 \sqrt{3}}$
$\frac{\pi}{6}+\frac{1}{2 \sqrt{3}}$
$\frac{\pi}{3}+\frac{1}{2 \sqrt{3}}$
$\frac{\pi}{6}-\frac{1}{2 \sqrt{3}}$
$$ \mathop {\lim }\limits_{n \to \infty }\left(\frac{1}{1^2+n^2}+\frac{2}{2^2+n^2}+\frac{3}{3^2+n^2}+\ldots+\frac{n}{n^2+n^2}\right)= $$
1
$\frac{1}{2} \log 2$
$2 \log 2$
0
The general solution of the differential equation $\frac{d y}{d x}=\frac{2 x^2-x y-y^2}{x^2-y^2}$ is
$\log \left|\frac{y^2-2 x^2}{x^2}\right|+\sqrt{2} \log \left|\frac{y-\sqrt{2} x}{y+\sqrt{2} x}\right| +2 \sqrt{2} \log |x|=C $
$\sqrt{2} \log \left|\frac{y^2-2 x^2}{x^2}\right|+\log \left|\frac{y-\sqrt{2} x}{y+\sqrt{2} x}\right| +2 \sqrt{2} \log |x|=C $
$\sqrt{2} \log \left|\frac{y^2+2 x^2}{x^2}\right|+\log \left|\frac{y+\sqrt{2} x}{y-\sqrt{2} x}\right| +2 \sqrt{2} \log |x|=C $
$\log \left|\frac{2 x^2-y^2}{x^2}\right|+\sqrt{2} \log \left|\frac{y+\sqrt{2} x}{y-\sqrt{2} x}\right| +\log |x|=C $
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