Consider the following
Statement I Kolbe's electrolysis of sodium propionate gives $n$-hexane as product.
Statement II In Kolbe's process $\mathrm{CO}_2$ is liberated at anode and $\mathrm{H}_2$ is liberated at cathode.
Correct answer is
The correct decreasing order of priority for the functional group of organic compounds in the IUPAC method of nomenclature is
A compound is formed by two elements $A$ and $B$. Atoms of the element $B$ (as anion) make ccp lattice and those of element $A$ (as cation) occupy all tetrahedral voids. The formula of the compound is
The mole fractions of glucose and water in aqueous glucose solution are 0.0244 and 0.9756 respectively. What is the weight percentage $(w / w)$ of glucose in this solution?
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