$$ \int \frac{(3 x-2) \tan \left(\sqrt{9 x^2-12 x+1}\right)}{\sqrt{9 x^2-12 x+1}} d x= $$
$\frac{1}{3} \sec ^2 \sqrt{9 x^2-12 x+1+C}$
$\frac{1}{3} \sec ^2 x+C$
$\frac{1}{2} \log \left|\sec \sqrt{9 x^2-12 x+1}\right|+C$
$\frac{1}{3} \log \left|\sec \sqrt{9 x^2-12 x+1}\right|+C$
$\int_{\frac{-\pi}{4}}^{\frac{\pi}{3}}\left|\tan \left(x-\frac{\pi}{6}\right)\right| d x=$
$\log \frac{\sqrt{3}-1}{\sqrt{6}}$
$\log (2 \sqrt{2}(\sqrt{3}+1))$
$\log \frac{\sqrt{3}+1}{\sqrt{6}}$
$\log (2 \sqrt{2}(\sqrt{3}-1))$
$$ \int_0^\pi \frac{x \sin x}{\sin ^2 x+2 \cos ^2 x} d x= $$
$\frac{\pi}{2}$
$\frac{\pi^2}{2}$
$\frac{\pi^2}{4}$
$\frac{\pi}{4}$
The area of the region lying between the curves $y=\sqrt{4-x^2}, y^2=3 x$ and the $Y$-axis is
$\frac{\pi}{3}-\frac{1}{2 \sqrt{3}}$
$\frac{\pi}{6}+\frac{1}{2 \sqrt{3}}$
$\frac{\pi}{3}+\frac{1}{2 \sqrt{3}}$
$\frac{\pi}{6}-\frac{1}{2 \sqrt{3}}$
AP EAPCET Papers
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