1
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{(3 x-2) \tan \left(\sqrt{9 x^2-12 x+1}\right)}{\sqrt{9 x^2-12 x+1}} d x= $$

A

$\frac{1}{3} \sec ^2 \sqrt{9 x^2-12 x+1+C}$

B

$\frac{1}{3} \sec ^2 x+C$

C

$\frac{1}{2} \log \left|\sec \sqrt{9 x^2-12 x+1}\right|+C$

D

$\frac{1}{3} \log \left|\sec \sqrt{9 x^2-12 x+1}\right|+C$

2
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$\int_{\frac{-\pi}{4}}^{\frac{\pi}{3}}\left|\tan \left(x-\frac{\pi}{6}\right)\right| d x=$

A

$\log \frac{\sqrt{3}-1}{\sqrt{6}}$

B

$\log (2 \sqrt{2}(\sqrt{3}+1))$

C

$\log \frac{\sqrt{3}+1}{\sqrt{6}}$

D

$\log (2 \sqrt{2}(\sqrt{3}-1))$

3
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^\pi \frac{x \sin x}{\sin ^2 x+2 \cos ^2 x} d x= $$

A

$\frac{\pi}{2}$

B

$\frac{\pi^2}{2}$

C

$\frac{\pi^2}{4}$

D

$\frac{\pi}{4}$

4
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The area of the region lying between the curves $y=\sqrt{4-x^2}, y^2=3 x$ and the $Y$-axis is

A

$\frac{\pi}{3}-\frac{1}{2 \sqrt{3}}$

B

$\frac{\pi}{6}+\frac{1}{2 \sqrt{3}}$

C

$\frac{\pi}{3}+\frac{1}{2 \sqrt{3}}$

D

$\frac{\pi}{6}-\frac{1}{2 \sqrt{3}}$