1
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the function $y=g(x)$ representing the slopes of the tangents drawn to the curve $y=3 x^4-5 x^3-12 x^2+18 x+3$ is strictly increasing, then the domain of $g(x)$ is

A

$\left[-\frac{1}{2}, \frac{4}{3}\right]$

B

$\left(\frac{-1}{2}, \frac{4}{3}\right)$

C

$R-\left(\frac{-1}{2}, \frac{3}{4}\right)$

D

$R-\left[\frac{-1}{2}, \frac{4}{3}\right]$

2
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider the following functions

I. $f(x)= \begin{cases}\frac{1}{2}-x & , x<\frac{1}{2} \\ \left(\frac{1}{2}-x\right)^2 & , x \geq \frac{1}{2}\end{cases}$

II. $f(x)=|3 x-1|$

III. $f(x)=x|x|$

IV. $f(x)=|x|$

Then, on $[0,1]$ Lagrange's mean value theorem is applicable to the functions

A

III, IV

B

II, III

C

I, III

D

II, IV

3
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{e^{\sin x}(\sin 2 x-8 \cos x)}{2(\sin x-3)^2} d x= $$

A

$e^{\sin x}(\sin x-3)+C$

B

$\frac{e^{\sin x}}{(\sin x-3)^2}+C$

C

$e^{\sin x}(\sin x-3)^2+C$

D

$\frac{e^{\sin x}}{\sin x-3}+C$

4
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $\int\left(3 t^2 \sin \frac{1}{t}-t \cos \frac{1}{t}\right) d t=f(t) \sin \left(\frac{1}{t}\right)+C$ then $f(2)=$

A

2

B

-12

C

8

D

-16