$$ \int_{\pi / 4}^{\pi / 3} \frac{\cos x-\sin x}{\sin 2 x} d x= $$
$\frac{1}{2} \log \left[\frac{(3+2 \sqrt{2})(2-\sqrt{3})}{\sqrt{3}}\right]$
$\frac{1}{2} \log \left[\frac{(3-2 \sqrt{2})(2+\sqrt{3})}{\sqrt{3}}\right]$
$\log \left[\frac{(3-2 \sqrt{2})(2-\sqrt{3})}{\sqrt{3}}\right]$
$\log \left[\frac{(3+2 \sqrt{2})(2-\sqrt{3})}{\sqrt{3}}\right]$
$$ \int_0^{\pi / 2} \frac{\sin x}{1+\cos x+\sin x} d x= $$
$\frac{\pi}{2}+\frac{1}{2} \log 2$
$\frac{\pi}{4}-\frac{1}{2} \log 2$
$\frac{\pi}{4}$
$\frac{3 \pi}{4}+\log 2$
$$ \mathop {\lim }\limits_{x \to \infty }\left[\frac{n+1}{n^2+1^2}+\frac{n+2}{n^2+2^2}+\frac{n+3}{n^2+3^2}+\ldots+\frac{n+2 n}{n^2+4 n^2}\right]= $$
$\tan ^{-1} 2+\frac{1}{2} \log 3$
$\frac{\pi}{4}+\frac{1}{2} \log 3$
$\tan ^{-1} 2+\frac{1}{2} \log 5$
$\frac{\pi}{4}+\frac{1}{2} \log 5$
$$ \int_0^\pi \frac{x \sin x}{1+\cos ^2 x} d x= $$
$\frac{\pi^2}{4}$
$\frac{\pi}{2}$
$\frac{\pi^2}{2}$
$\frac{\pi}{4}$
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