1
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $630^{\circ}<\theta<810^{\circ}$ and $\tan \theta=-\frac{7}{24}$, then $\cos \left(\frac{\theta}{4}\right)=$

A

$-\sqrt{\frac{7+5 \sqrt{2}}{10 \sqrt{2}}}$

B

$\sqrt{\frac{7+5 \sqrt{2}}{2 \sqrt{2}}}$

C

$-\sqrt{\frac{5 \sqrt{2}-7}{10 \sqrt{2}}}$

D

$\sqrt{\frac{5 \sqrt{2}-7}{2 \sqrt{2}}}$

2
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For $\theta \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$ if $2 \cos \theta+\sin \theta=1$ and $7 \cos \theta+6 \sin \theta=k$, then the possible values of $k$ are

A

8,-2

B

6,2

C

12,4

D

7,6

3
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \sum\limits_{k=0}^{12} \frac{1}{\sin \left((k+1) \frac{\pi}{6}+\frac{\pi}{4}\right) \sin \left(\frac{k \pi}{6}+\frac{\pi}{4}\right)}= $$

A

$2(\sqrt{3}+1)$

B

$2(3-\sqrt{3})$

C

$2(2-\sqrt{3})$

D

$2(\sqrt{3}-1)$

4
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The number of solutions of the equation $2 \sin ^2 \theta-3 \cos ^2 \theta=\sin \theta \cos \theta$ lying in the intervals $(-\pi, \pi)$ is

A

2

B

4

C

3

D

1