1
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The circle $x^2+y^2-8 x-12 y+\alpha=0$ lies in the first quadrant without touching the coordinate axes. If $(6,6)$ is an interior point to the circle, then
A
$4<\alpha<6$
B
$6<\alpha<16$
C
$16<\alpha<48$
D
$36<\alpha<48$
2
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The equation of the circle whose diameter is the common chord of the circles $x^2+y^2-6 x-7=0$ and $x^2+y^2-10 x+16=0$ is
A
$8 x^2+8 y^2-92 x+197=0$
B
$x^2+y^2-23 x+197=0$
C
$x^2+y^2-\frac{23}{2} x+\frac{197}{4}=0$
D
$4 x^2+4 y^2-46 x+197=0$
3
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If the locus of the mid-point of the chords of the circle $x^2+y^2=25$, which subtend a right angle at the origin is given by $\frac{x^2}{\alpha^2}+\frac{y^2}{\alpha^2}=1$, then $|\alpha|=$
A
$\frac{2}{5}$
B
$\frac{5}{\sqrt{2}}$
C
$\frac{2}{25}$
D
$5 \sqrt{2}$
4
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The radical centre of the circles $x^2+y^2+2 x+3 y+1=0$, $x^2+y^2+x-y+3=0, x^2+y^2-3 x+2 y+5=0$
A
$\left(-\frac{7}{38}, \frac{6}{19}\right)$
B
$\left(\frac{6}{19}, \frac{14}{19}\right)$
C
$\left(\frac{14}{19}, \frac{6}{19}\right)$
D
$\left(\frac{2}{19}, \frac{3}{19}\right)$
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