1
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The general solution of the differential equation $\left(x \sin \frac{y}{x}\right) d y=\left(y \sin \frac{y}{x}-x\right) d x$ is
A
$\cos \frac{x}{y}=\log _6 x+c$
B
$\cos \frac{x}{y}=\log _e y+c$
C
$\cos \frac{y}{x}=\log _e x+c$
D
$\cos \frac{y}{x}=\log _e y+c$
2
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
Find the dimension formula of $\frac{a}{b}$ in the equation $F=a \sqrt{x}+b t^2$, where $F$ is force, $x$ is distance and $t$ is time.
A
$\left[M^0 L^{-1 / 2} T^2\right]$
B
$\left[M^0 L^0 T^{3 / 2}\right]$
C
$\left[M^0 L^1 T^{-4}\right]$
D
$\left[M^0 L^{3 / 2} T^4\right]$
3
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The relation between time $t$ and displacement $x$ is $t=\alpha x^2+\beta x$, where $\alpha$ and $\beta$ are constants. If $v$ is the velocity, the retardation is
A
$2 \alpha v^3 \beta^2$
B
$2 \alpha \beta v^3$
C
$-2 \beta v^3$
D
$2 \alpha v^3$
4
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If two stones are projected at angle $\theta$ and $\left(90^{\circ}-\theta\right)$ respectively with horizontal with a speed of $20 \mathrm{~ms}^{-1}$. If second stone rises 10 m higher than the first stone then, the angle of projection $\theta$ is (acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
A
$45^{\circ}$
B
$30^{\circ}$
C
$60^{\circ}$
D
$20^{\circ}$
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