1
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

Let $$z_k=\cos \left(\frac{2 k \pi}{10}\right)+i \sin \left(\frac{2 k \pi}{10}\right) ; k=1,2, \ldots \ldots \ldots$$ 9, then $$\frac{1}{10}\left\{\left|1-z_1\right|\left|1-z_2\right| \ldots .\left|1-z_a\right|\right\}$$ equals to

A
0
B
1
C
2
D
3
2
VITEEE 2022
MCQ (Single Correct Answer)
+1
-0

The condition in order that $$Z_1, Z_2, Z_3$$ are vertices of an isosceles triangle right angled at $$z_2$$, is

A
$$\left(Z_1-Z_3\right)^2=3\left(Z_1-Z_2\right)\left(Z_2-Z_3\right)$$
B
$$\left(Z_1-Z_3\right)^2=3\left(Z_2-Z_1\right)\left(Z_2-Z_3\right)$$
C
$$\left(Z_1-Z_3\right)^2=2\left(Z_1-Z_2\right)\left(Z_2-Z_3\right)$$
D
$$\left(Z_1-Z_3\right)^2=2\left(Z_2-Z_1\right)\left(Z_2-Z_3\right)$$
3
VITEEE 2021
MCQ (Single Correct Answer)
+1
-0

If $$(1+i)(2 i+1)(1+3 i) \ldots(1+n i)=x+i y$$, then $$2 \cdot 5 \cdot 10 \ldots\left(1+n^2\right)$$ is equal to

A
1
B
$$i$$
C
$$x^2+y^2$$
D
$$1+n^2$$
4
VITEEE 2021
MCQ (Single Correct Answer)
+1
-0

The non-zero solutions of the equation $$z^2+|z|=0$$, where $$z$$ is a complex number, are

A
$$\pm 1$$
B
$$\pm i$$
C
$$1 \pm i$$
D
$$\pm 1 \pm i$$
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