1
VITEEE 2021
MCQ (Single Correct Answer)
+1
-0

If $$\theta=\frac{\pi}{2^n+1}$$, then the value of $$2^n \cos \theta \cos 2 \theta \cos 2^2 \theta \ldots \cos 2^{n-1} \theta$$ is

A
$$\sin \theta$$
B
$$\frac{\pi}{2}$$
C
0
D
1
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