1
NDA 2018 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
What is the adjoint of the matrix $$\left( {\matrix{ {\cos ( - \theta )} & { - \sin ( - \theta )} \cr { - \sin ( - \theta )} & {\cos ( - \theta )} \cr } } \right)$$ ?
A
$$\left( {\matrix{ {\cos \theta } & { - \sin \theta } \cr { - \sin \theta } & {\cos \theta } \cr } } \right)$$
B
$$\left( {\matrix{ {\cos \theta } & {\sin \theta } \cr {\sin \theta } & {\cos \theta } \cr } } \right)$$
C
$$\left( {\matrix{ {\cos \theta } & {\sin \theta } \cr { - \sin \theta } & {\cos \theta } \cr } } \right)$$
D
$$\left( {\matrix{ {\cos \theta } & { - \sin \theta } \cr {\sin \theta } & {\cos \theta } \cr } } \right)$$
2
NDA 2018 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
What should be the value of x, so that the matrix $$\left( {\matrix{ 2 & 4 \cr { - 8} & x \cr } } \right)$$ does not have an inverse?
A
16
B
$$-$$ 16
C
8
D
$$-$$8
3
NDA 2018 Paper 1
MCQ (Single Correct Answer)
+2.5
-0.83
If $$A = \left( {\matrix{ 1 & 2 \cr 2 & 3 \cr } } \right)$$ and $${A^2} - kA - {I_2} = O$$, where I2 is the 2 $$\times$$ 2 identity matrix, then what is the value of k?
A
4
B
$$-$$ 4
C
8
D
$$-$$ 8
4
NDA 2018 Paper 1
MCQ (Single Correct Answer)
+2.5
-0.83
What is the inverse of the matrix $$A = \left( {\matrix{ {\cos \theta } & {\sin \theta } & 0 \cr { - \sin \theta } & {\cos \theta } & 0 \cr 0 & 0 & 1 \cr } } \right)$$ ?
A
$$\left( {\matrix{ {\cos \theta } & { - \sin \theta } & 0 \cr {\sin \theta } & {\cos \theta } & 0 \cr 0 & 0 & 1 \cr } } \right)$$
B
$$\left( {\matrix{ {\cos \theta } & 0 & {\sin \theta } \cr 0 & 1 & 0 \cr {\sin \theta } & 0 & {\cos \theta } \cr } } \right)$$
C
$$\left( {\matrix{ 1 & 0 & 0 \cr 0 & {\cos \theta } & { - \sin \theta } \cr 0 & {\sin \theta } & {\cos \theta } \cr } } \right)$$
D
$$\left( {\matrix{ {\cos \theta } & {\sin \theta } & 0 \cr { - \sin \theta } & {\cos \theta } & 0 \cr 0 & 0 & 1 \cr } } \right)$$
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