1
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

If $$x d y / d x=x^2+y-2, y(1)=1$$, then $$y(2)$$ is equal to

A
2
B
4
C
1
D
8
2
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

The sum of all the numbers of four different digits that can be made using the digits 0, 1, 2 and 3 is

A
26664
B
399996
C
38664
D
None of these
3
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

If $$x^n=a_0+a_1(1+x)+a_2(1+x)^2+\ldots \ldots \ldots+ a_n(1+x)^n=b_0+b_1(1-x)+b_2(1-x)^2+\ldots . .+ b_n(1-x)^n$$, then for $$n=201,\left(a_{101}, b_{101}\right)$$ is equal to

A
$$-{ }^{201} C_{101},-201 C_{101}$$
B
$${ }^{201} C_{101},-{ }^{201} C_{101}$$
C
$$-{ }^{201} C_{101},{ }^{201} C_{101}$$
D
$${ }^{201} C_{101},{ }^{201} C_{101}$$
4
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

The solution of differential equation $$y y^{\prime}=x\left(\frac{y^2}{x^2}+\frac{f\left(y^2 / x^2\right)}{f^{\prime}\left(y^2 / x^2\right)}\right)$$ is

A
$$x^2 f\left(\frac{y^2}{x^2}\right)=c$$
B
$$x^2 f\left(\frac{y^2}{x^2}\right)=c^2 y^2$$
C
$$f\left(\frac{y^2}{x^2}\right)=c x^2$$
D
$$f\left(\frac{y^2}{x^2}\right)=\frac{c y}{x}$$
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