1
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

The solution of $$d y / d x=1+x+y+x y$$ is

A
$$x+y=c(1+x y)$$
B
$$\log (1+x)+x+y=c$$
C
$$\log (1+y)=x+\frac{x^2}{2}+C$$
D
None of these
2
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

A unit vector perpendicular to both the vectors $$\hat{\mathbf{j}}+\hat{\mathbf{k}}$$ and $$\hat{\mathbf{i}}+\hat{\mathbf{k}}$$ is

A
$$\frac{\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}}{\sqrt{3}}$$
B
$$\frac{-\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}}{\sqrt{3}}$$
C
$$\frac{\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}}{\sqrt{3}}$$
D
$$\frac{\hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}}{\sqrt{3}}$$
3
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

If $$\cot ^{-1}(y)=\cot ^{-1}(x)+\cot ^{-1}\left(\frac{x^2-1}{2 x}\right)$$, then the value of $$y$$ is

A
$$\frac{3 x-x^3}{3 x^2-1}$$
B
$$\frac{x^3-3 x}{3 x^2-1}$$
C
$$\frac{x^3-3 x}{1+3 x^2}$$
D
$$\frac{3 x+x^3}{1+3 x^2}$$
4
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

$$\tan ^{-1}\left(\frac{1}{5}\right)+\tan ^{-1}\left(\frac{1}{7}\right)+\tan ^{-1}\left(\frac{1}{3}\right)+\tan ^{-1}\left(\frac{1}{8}\right)$$ equals to

A
$$\frac{\pi}{3}$$
B
$$\frac{\pi}{6}$$
C
$$\frac{\pi}{4}$$
D
$$\frac{2 \pi}{3}$$
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