1
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

In a $$n$$-$$p$$-$$n$$ transistor $$10^{10}$$ electrons enter the emitter in $$10^{-6}$$ s. $$6 \%$$ of the other electrons are lost in the base. The current transfer ratio will be.

A
0.98
B
0.97
C
0.96
D
0.94
2
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

The position of a projectile launched from the origin at $$t=0$$ is given $$\mathbf{r}=(40 \hat{\mathbf{i}}+50 \hat{\mathbf{j}}) \mathrm{m}$$ at $$t=4 \mathrm{~s}$$. If the projectile was launded at an angle $$\theta$$ from the horizontal, then $$\theta$$ is (take, $$g=10 \mathrm{~m} / \mathrm{s}^2$$ )

A
$$\tan ^{-1}\left(\frac{2}{3}\right)$$
B
$$\tan ^{-1}\left(\frac{3}{2}\right)$$
C
$$\tan ^{-1}\left(\frac{13}{8}\right)$$
D
$$\tan ^{-1}\left(\frac{4}{5}\right)$$
3
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

Electric field in the region is given by $$\mathbf{E}=\left(M / x^4\right) \hat{\mathbf{i}}$$, then the correct expression for the potential in the region is (assume potential at infinity is zero)

A
$$M / 3 x^3$$
B
$$M x^3$$
C
$$M / 3 x^4$$
D
$$M / x^2$$
4
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

The gravitational field in a region is given by $$\mathbf{E}=5 \mathrm{~N} / \mathrm{kg} \hat{\mathbf{i}}+12 \mathrm{~N} / \mathrm{kg} \hat{\mathbf{j}}$$. The change in the gravitational potential energy of a particle of mass $$1 \mathrm{~kg}$$ when it is taken from the origin to a point ($$5 \hat{\mathbf{i}}-5 \hat{\mathbf{j}}$$) is

A
$$71 \mathrm{~J}$$
B
$$13 \sqrt{58} \mathrm{~J}$$
C
$$-71 \mathrm{~J}$$
D
$$35 \mathrm{~J}$$
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