1
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

Let $$z_k=\cos \left(\frac{2 k \pi}{10}\right)+i \sin \left(\frac{2 k \pi}{10}\right) ; k=1,2, \ldots \ldots \ldots$$ 9, then $$\frac{1}{10}\left\{\left|1-z_1\right|\left|1-z_2\right| \ldots .\left|1-z_a\right|\right\}$$ equals to

A
0
B
1
C
2
D
3
2
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

If $$m$$ and $$n$$ are order and degree of the question $$\left(\frac{d^2 y}{d x^2}\right)^4+8 \frac{\left(d^2 y / d x^2\right)^3}{\left(d^4 y / d x^4\right)^5}+\left(\frac{d^4 y}{d x^4}\right)=x^2+4$$, then $$m-n$$ is equal to

A
2
B
6
C
$$-$$4
D
$$-$$2
3
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

If $$\left(\sin ^{-1} x\right)^2-\left(\cos ^{-1} x\right)^2=a \pi^2$$, then the range of $$a$$ is

A
$$\left[\frac{-3}{4}, \frac{1}{4}\right]$$
B
$$\left[\frac{-3}{4}, \frac{3}{4}\right]$$
C
$$[-1,1]$$
D
$$\left[-1, \frac{3}{4}\right]$$
4
VITEEE 2023
MCQ (Single Correct Answer)
+1
-0

The equation $$3 \cos ^{-1} x-\pi x-\pi / 2=0$$ has

A
one negative solution
B
one positive solution
C
no solution
D
more than one solution
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