1
TS EAMCET 2023 (Online) 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\frac{2 x^3+3 x^2+3 x+5}{\left(x^2+1\right)\left(x^2+2\right)}$ is expanded in terms of the powers of $x$, then the coefficient of $x^5$ is

A

0

B

$\frac{-5}{4}$

C

$\frac{17}{8}$

D

$\frac{9}{8}$

2
TS EAMCET 2023 (Online) 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \sin 6^{\circ}+\sin 54^{\circ}+\sin 126^{\circ}+\cos 156^{\circ}= $$

A

$\frac{\sqrt{5}+1}{4}$

B

$\frac{\sqrt{5}-1}{4}$

C

$-\frac{1}{2}$

D

$\frac{3}{4}$

3
TS EAMCET 2023 (Online) 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\tan \alpha=\frac{-12}{5}, \cot \beta=\frac{7}{24}, \alpha$ does not belong to second quadrant and $\beta$ does not belong to first quadrant, then $\sqrt{13} \sin \frac{\alpha}{2}+\cos \frac{\beta}{2}+\tan \frac{\alpha}{2} \cot \frac{\beta}{2}=$

A

$\frac{31}{10}$

B

$\frac{19}{10}$

C

$\frac{21}{10}$

D

$\frac{-9}{10}$

4
TS EAMCET 2023 (Online) 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$\cos \frac{\pi}{7} \cos \frac{2 \pi}{7} \cos \frac{3 \pi}{7} \cos \frac{\pi}{14} \cos \frac{3 \pi}{14} \cos \frac{5 \pi}{14}=$

A

$\frac{1}{16}\left[\sin \frac{\pi}{7}+\sin \frac{2 \pi}{7}+\sin \frac{3 \pi}{7}\right]$

B

$\frac{1}{8}\left[\sin \frac{2 \pi}{7}+\sin \frac{3 \pi}{7}-\sin \frac{\pi}{7}\right]$

C

$\frac{1}{32}\left[\sin \frac{2 \pi}{7}+\sin \frac{3 \pi}{7}-\sin \frac{\pi}{7}\right]$

D

$\frac{1}{32}\left[\sin \frac{\pi}{7}-\sin \frac{2 \pi}{7}+\sin \frac{3 \pi}{7}\right]$

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