1
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Equation of the plane through the mid-point of the line segment joining the points $A(4,5,-10)$ and $B(-1,2,1)$ and perpendicular to $A B$ is
A
$10 x+6 y-22 z+135=0$
B
$10 x+6 y-22 z-135=0$
C
$5 x+3 y+11 z=135$
D
$10 x+6 y-22 z+185=0$
2
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$$ \lim \limits_{x \rightarrow 1} \frac{(2 x-3)(\sqrt{x}-1)}{2 x^2+x-3}= $$
A
$\frac{1}{10}$
B
$-\frac{1}{10}$
C
$\frac{2}{5}$
D
$-\frac{2}{5}$
3
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If $\mathbf{a}$ is a vector such that $\mathbf{a} \times \hat{\mathbf{i}}=\hat{\mathbf{j}}+\hat{\mathbf{k}}$ and $\mathbf{a} \cdot \hat{\mathbf{i}}=1$, then equation of the line passing through the point $\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}$ and parallel to $\mathbf{a}$ is
A
$\mathbf{r}=(t+1) \hat{i}+(1-t) \hat{j}+(t+1) \hat{k}$
B
$r=(t+1) \hat{\mathbf{i}}-(2 t-1) \hat{\mathbf{j}}+t \hat{\mathbf{k}}$
C
$\mathbf{r}=\hat{\mathbf{i}}+t \hat{\mathbf{j}}-t \hat{\mathbf{k}}$c
D
$\mathbf{r}=5 t \hat{\mathbf{i}}+7 t \hat{\mathbf{j}}+\hat{\mathbf{k}}$
4
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The equation of the normal at $t=\frac{\pi}{2}$ to the curve $x=2 \sin t, y=2 \cos t$ is
A
$x=2$
B
$y=2 x+3$
C
$y=0$
D
$y=3$
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