1
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Assertion (A) The curves $y^2=4 x$ and $x^2=-2 y$ intersect at $(1,2)$ orthogonally.

Reason (R) If the product of the slopes of the tangents drawn to two curves at their point of intersection is -1 , then the curves are said to cut each other orthogonally.

A

(A) is true, (R) is true and (R) is the correct explanation for (A).

B

(A) is true, (R) is true, but (R) is not the correct explanation for (A).

C

(A) is true but (R) is false.

D

(A) is false but (R) is true.

2
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $f(x)=\left\{\begin{array}{cc}1+6 x-3 x^2 & x \leq 1 \\ x+\log _2\left(b^2+7\right) & x>1\end{array}\right.$. Then, the set of all possible values of $b$ such that $f(1)$ is the maximum value of $f(x)$ is

A

$[-1,1]$

B

$[0,1]$

C

$[0,2]$

D

$[-1,0]$

3
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $g(x)$ be the anti-derivative of $f(x)$. Then, the function for which $\log _e\left(1+(g(x))^2\right)+c$ is an anti-derivative is

A

$\left(1+(g(x))^2\right) g^{\prime}(x) f(x)$

B

$\frac{-2 f(x) g(x)}{1+g(x)}$

C

$\frac{2 f(x) g(x)}{1+(g(x))^2}$

D

$\frac{2 g(x)}{1+(g(x))^2}$

4
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=\int\left[\tan ^2 x+\cot ^2 x+\frac{4\left(\sin ^3 x+\cos ^3 x\right)}{\sin ^2 2 x}\right] d x$ and $f\left(\frac{\pi}{4}\right)=0$, then $3\left[f\left(\frac{\pi}{6}\right)+2\right]=$

A

$\frac{\pi}{2}$

B

$\frac{\pi}{4}$

C

0

D

$\frac{-\pi}{2}$

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