1
TS EAMCET 2022 (Online) 18th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider following reaction, where

(A) the change in the functional group and

(B) the corresponding change in the hybridisation from starting to the final product $A$ and $B$ are

TS EAMCET 2022 (Online) 18th July Morning Shift Chemistry - Compounds Containing Nitrogen Question 12 English

A

TS EAMCET 2022 (Online) 18th July Morning Shift Chemistry - Compounds Containing Nitrogen Question 12 English Option 1

B

TS EAMCET 2022 (Online) 18th July Morning Shift Chemistry - Compounds Containing Nitrogen Question 12 English Option 2

C

TS EAMCET 2022 (Online) 18th July Morning Shift Chemistry - Compounds Containing Nitrogen Question 12 English Option 3

D

TS EAMCET 2022 (Online) 18th July Morning Shift Chemistry - Compounds Containing Nitrogen Question 12 English Option 4

2
TS EAMCET 2022 (Online) 18th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Which of the following reactions will give benzophenone as major product?

(A) Benzoyl chloride + benzene $+\mathrm{AlCl}_3$ (anhyd).

(B) Benzoyl chloride + phenylmagnesium bromide

     (excess)

(C) Benzoyl chloride + diphenyl cadmium

A

A and B only

B

B and C only

C

A and C only

D

A, B and C

3
TS EAMCET 2022 (Online) 18th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

The reagent that can reduce the carboxylic acid group to the corresponding alcohol is

A

$\mathrm{NaBH}_4 / \mathrm{H}_3 \mathrm{O}^{+}$

B

$\mathrm{B}_2 \mathrm{H}_6 / \mathrm{H}_3 \mathrm{O}^{+}$

C

$\mathrm{Zn}-\mathrm{Hg} /$ conc. HCl

D

$\mathrm{H}_2, \mathrm{Pd} / \mathrm{C}$

4
TS EAMCET 2022 (Online) 18th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

The starting material that produce pentanamine by Hoffmann bromamide reaction is

A

$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CN}$

B

$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CONH}_2$

C

$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NCO}$

D

$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CONH}_2$

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