1
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $S(a, b)$ is a fixed point and $P(\alpha, \beta)$ is such a variable point that $4\left[(x-a)^2+(y-b)^2\right]=(\alpha x+\beta y+7)^2$ represents a parabola, then the locus of $P(\alpha, \beta)$ is

A

$\beta^2=4 \alpha$

B

$\alpha^2+\beta^2=4$

C

$\frac{\alpha^2}{4}+\frac{\beta^2}{2}=1$

D

$(\alpha+\beta)^2=4$

2
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $P(-3,2)$ is an end point of the focal chord $P Q$ of the parabola $y^2+4 x+4 y=0$, then the slope of the normal drawn at $Q$ is

A

$\frac{-1}{2}$

B

2

C

$\frac{1}{2}$

D

-2

3
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Equation of a common tangent to the circle $x^2+y^2=4$ and to the ellipse $2 x^2+25 y^2=50$ is

A

$\sqrt{2} x+\sqrt{21} y+\sqrt{23}=0$

B

$\sqrt{2} x-\sqrt{21} y+2 \sqrt{23}=0$

C

$\sqrt{19} x-\sqrt{2} y+2 \sqrt{21}=0$

D

$\sqrt{19} x-y+2 \sqrt{20}=0$

4
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The $\theta$ is the angle made by the common tangent to the circle $x^2+y^2=16$ and the ellipse $\frac{x^2}{25}+\frac{y^2}{9}=1$ with positive $X$-axis, then $\cos 2 \theta=$

A

$\frac{-2}{3}$

B

$\frac{5}{6}$

C

$\frac{-1}{8}$

D

$\frac{1}{8}$

TS EAMCET Papers

All year-wise previous year question papers