1
TS EAMCET 2020 (Online) 10th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A tetrahedron has vertices $O(0,0,0), A(1,2,1)$, $B(2,1,3), C(-1,1,2)$. If $\theta$ is the angle between the faces $O A B$ and $A B C$, then $\cos \theta=$

A

$\frac{1}{\sqrt{2}}$

B

$\frac{19}{35}$

C

$\frac{\sqrt{3}}{2}$

D

$\frac{17}{31}$

2
TS EAMCET 2020 (Online) 10th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $\log (1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+\ldots \ldots \infty$ and $\mathop {\lim }\limits_{x \to 0} \frac{\log (1+x)^{1+x}}{x^2}-\frac{1}{x}=k$, then $12 k=$

A

1

B

3

C

6

D

9

3
TS EAMCET 2020 (Online) 10th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=\left\{\begin{array}{ll}k, & \text { for } x=1 \\ \frac{(9 x-1)(\sqrt{x}-1)}{3 x^2+2 x-5}, & \text { for } x \neq 1\end{array}\right.$ is continuous on $[0, \infty)$, then $k=$

A

$\frac{1}{16}$

B

$\frac{1}{8}$

C

$\frac{1}{4}$

D

$\frac{1}{2}$

4
TS EAMCET 2020 (Online) 10th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

let $g(x) \neq 0, g^{\prime}(x) \neq 0, f(x) \neq 0, f^{\prime}(x) \neq 0$. If

$F(x)=f(x) g(x), G(x)=f^{\prime}(x) g^{\prime}(x)$ and

$F^{\prime}(x)=G(x) H(x)=F(x) K(x)$, then $H(x)+K(x)=$

A

$\frac{f^{\prime}}{f}+\frac{f}{f^{\prime}}+\frac{g}{g^{\prime}}$

B

$\frac{f^{\prime}}{f}+\frac{g}{g^{\prime}}+\frac{g^{\prime}}{g}$

C

$\frac{f^{\prime} g^{\prime}+f g}{f f^{\prime} g g^{\prime}}$

D

$\frac{f^{\prime}}{f}+\frac{g}{g^{\prime}}+\frac{f}{f^{\prime}}+\frac{g^{\prime}}{g}$

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