1
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $P$ be the pair of lines represented by $2 x^2-5 x y+2 y^2+6 x-3 y=0$ and consider the following independent statements

(i) $\alpha$ is the $x$ coordinate of the point of intersection of the pair of lines $P$.

(ii) $\beta$ is the slope of one of the lines of $P$ passing through origin.

(iii) $\gamma$ is the constant term in the equation of the pair of angular bisectors of $P$.

Then,

A

$\beta<\gamma<\alpha$

B

$\alpha<\beta=\gamma$

C

$\alpha=\beta<\gamma$

D

$\gamma<\alpha<\beta$

2
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The combined equation of the diagonals of the parallelogram formed by the lines

$$ \left(7 x^2-4 x y+8 y^2\right)^2+(4 x-8 y-32)\left(7 x^2-4 x y+8 y^2\right)=0 $$

is

A

$x^2-x y+y^2+3 x-15 y=0$

B

$3 x^2-6 x y-2 y^2-15 x-17 y=0$

C

$3 x^2-5 x y-2 y^2-24 x-8 y=0$

D

$x^2-x y+y^2+15 x-12 y=0$

3
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the origin lies on a diameter of the circle $x^2+y^2-4 x-2 y-4=0$, then the equation of the circle passing through the end points of that diameter and the point $(1,2)$ is

A

$x^2+y^2-2 x-4 y=0$

B

$3 x^2+3 y^2-19 x+8 y-12=0$

C

$7 x^2+7 y^2-31 x-28 y+17=0$

D

$x^2+y^2=5$

4
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\alpha \neq-4$ and $(2, \alpha)$ is the mid-point of a chord of the circle $x^2+y^2-4 x+8 y+6=0$, then the values of the $y$-intercept of the chord lie in the interval

A

$(-4-\sqrt{14},-4+\sqrt{14})$

B

$(-4,4)$

C

$(4-\sqrt{14}, 4+\sqrt{14})$

D

$(-2,2)$

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