1
TG EAPCET 2025 (Online) 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{x^2 \tan ^{-1} x}{\left(1+x^2\right)^2} d x= $$

A

$\frac{\left(\tan ^{-1} x\right)^2}{4}-\frac{x \tan ^{-1} x}{2\left(1+x^2\right)}+\frac{1-x^2}{4\left(1+x^2\right)}+C$

B

$\frac{\left(\tan ^{-1} x\right)^2}{4}-\frac{4 x \tan ^{-1} x+1-x^2}{8\left(1+x^2\right)}+C$

C

$\frac{\left(\tan ^{-1} x\right)^2}{4}-\frac{x \tan ^{-1} x}{\left(1+x^2\right)}-\frac{1-x^2}{4\left(1+x^2\right)}+C$

D

$\frac{(\tan x)^2}{4}+\frac{4 x \tan ^{-1} x-1+x^2}{4\left(1+x^2\right)}+C$

2
TG EAPCET 2025 (Online) 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{\log x}{(1+x)^3} d x= $$

A

$\frac{1}{2}\left[\frac{1}{1+x}+\frac{\log x}{(1+x)^2}-\log \left(x^2+x\right)\right]+C$

B

$\frac{1}{2}\left[\frac{1}{1+x}-\frac{\log x}{(1+x)}-\log \left(1+x^2\right)\right]+C$

C

$\frac{1}{2}\left[\frac{1}{1+x}+\frac{\log x}{(1+x)^2}-\log \left(1+x^2\right)\right]+C$

D

$\frac{1}{2}\left[\frac{1}{1+x}-\frac{\log x}{(1+x)^2}+\log \left(\frac{x}{1+x}\right)\right]+C$

3
TG EAPCET 2025 (Online) 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^{\pi / 4} \frac{1}{5 \cos ^2 x+16 \sin ^2 x+8 \sin x \cos x} d x= $$

A

$\tan ^{-1}\left(\frac{4}{5}\right)$

B

$2 \tan ^{-1}\left(\frac{3}{5}\right)$

C

$\frac{1}{8} \tan ^{-1}\left(\frac{8}{9}\right)$

D

$\frac{1}{4} \tan ^{-1}\left(\frac{7}{8}\right)$

4
TG EAPCET 2025 (Online) 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_8^{18} \frac{1}{(x+2) \sqrt{x-3}} d x= $$

A

$\frac{\pi}{6 \sqrt{5}}$

B

$\frac{\pi}{6}$

C

$\frac{\pi}{3}$

D

$\frac{\pi}{3 \sqrt{5}}$

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