1
KCET 2025
MCQ (Single Correct Answer)
+1
-0

The equation of the line through the point $(0,1,2)$ and perpendicular to the line $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}$ is

A
$\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{-3}$
B
$\frac{\mathrm{x}}{-3}=\frac{\mathrm{y}-1}{4}=\frac{\mathrm{z}-2}{3}$
C
$\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{3}$
D
$\frac{x}{3}=\frac{y-1}{-4}=\frac{z-2}{3}$
2
KCET 2025
MCQ (Single Correct Answer)
+1
-0

A line passes through $(-1,-3)$ and perpendicular to $x+6 y=5$. Its $x$ intercept is

A
$\frac{1}{2}$
B
$-\frac{1}{2}$
C
-2
D
2
3
KCET 2025
MCQ (Single Correct Answer)
+1
-0

The length of the latus rectum of $x^2+3 y^2=12$ is

A
$\frac{2}{3}$ units
B
$\frac{1}{3}$ units
C
$\frac{4}{\sqrt{3}}$ units
D
24 units
4
KCET 2025
MCQ (Single Correct Answer)
+1
-0
$\lim _{x \rightarrow 1} \frac{x^4-\sqrt{x}}{\sqrt{x}-1}$ is
A
0
B
7
C
Does not exist
D
$\frac{1}{2}$
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