$$ \text { Given below and the atomic masses of the elements: } $$
$$ \begin{array}{|l|l|l|l|l|l|l|l|l|l|} \hline \text { Element: } & \mathrm{Li} & \mathrm{Na} & \mathrm{Cl} & \mathrm{~K} & \mathrm{Ca} & \mathrm{Br} & \mathrm{Sr} & \mathrm{I} & \mathrm{Ba} \\ \hline \text { Atomic Mass }\left(\mathrm{g} \mathrm{~mol}^{-1}\right): & 7 & 23 & 35.5 & 39 & 40 & 80 & 88 & 127 & 137 \\ \hline \end{array} $$
$$ \text { Which of the following doesn't form triad? } $$If $\mathrm{A}=\left\{\mathrm{x}: \mathrm{x}\right.$ is an integer and $\left.\mathrm{x}^2-9=0\right\}$
$B=\{x: x$ is a natural number and $2 \leq x<5\}$
$\mathrm{C}=\{\mathrm{x}: \mathrm{x}$ is a prime number $\leq 4\}$
Then $(B-C) \cup A$ is,
$A$ and $B$ are two sets having 3 and 6 elements respectively. Consider the following statements.
Statement (I): Minimum number of elements in AUB is 3
Statement (II): Maximum number of elements in AB is 3 Which of the following is correct?