1
AP EAPCET 2024 - 21th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If $\cos x \frac{d y}{d x}-y \sin x=6 x,\left(0 < x < \frac{\pi}{2}\right)$ and $y\left(\frac{\pi}{3}\right)=0$, then $y\left(\frac{\pi}{6}\right)=$
A
$\frac{-\pi^2}{4 \sqrt{3}}$
B
$\frac{-\pi^2}{2}$
C
$\frac{-\pi^2}{2 \sqrt{3}}$
D
$\frac{\pi^2}{2 \sqrt{3}}$
2
AP EAPCET 2024 - 21th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$\frac{d y}{d x}=\frac{y+x \tan \frac{y}{x}}{x} \Rightarrow \sin \frac{y}{x}=$

A

$c x^2$

B

$c x$

C

$c x^3$

D

$c x^4$

3
AP EAPCET 2024 - 21th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The length of the side of a cube is $1.2 \times 10^{-2} \mathrm{~m}$. Its volume up to correct significant figure is
A
$1.732 \times 10^{-6} \mathrm{~m}^3$
B
$1.73 \times 10^{-6} \mathrm{~m}^3$
C
$1.70 \times 10^{-6} \mathrm{~m}^3$
D
$1.7 \times 10^{-6} \mathrm{~m}^3$
4
AP EAPCET 2024 - 21th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The velocity of a particle is given by the equation $v(x)=3 x^2-4 x$, where $x$ is the distance covered by the particle. The expression for its acceleration is
A
$(6 x-4)$
B
$6\left(3 x^2-4 x\right)$
C
$\left(3 x^2-4 x\right)(6 x-4)$
D
$(6 x-4)^2$
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