1
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In $\triangle A B C$, if $r_1=4, r_2=8$ and $r_3=24$, then $a=$
A
0
B
$\frac{16}{\sqrt{5}}$
C
$16 \sqrt{5}$
D
$\sqrt{5}$
2
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If a circle is inscribed in an equilateral triangle of side $a$, then the area of any square (in sq units) inscribed in this circle is
A
$\frac{2 a^2}{3}$
B
$\sqrt{3} \frac{a^2}{2}$
C
$\frac{a^2}{2 \sqrt{3}}$
D
$\frac{a^2}{6}$
3
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Match the items of List I with those of List II (here, $\Delta$ denotes the area of $\triangle A B C$ )
List I List II
(A) $$
\sum \cot A
$$
(i) $$
(a+b+c)^2 \frac{1}{4 \Delta}
$$
(B) $$
\sum \cot \frac{A}{2}
$$
(ii) $$
\left(a^2+b^2+c^2\right) \frac{1}{4 \Delta}
$$
(C) If $\tan A: \tan B: \tan C=1: 2: 3$, then $\sin A: \sin B: \sin C=$ (iii) $$
8: 6: 5
$$
(D) $$
\begin{aligned}
&\text { If } \cot \frac{A}{2}: \cot \frac{B}{2}: \cot \frac{C}{2}=3: 7: 9\\
&\text { then } a: b: c=
\end{aligned}
$$
(iv) $$
12: 5: 13
$$
(v) $$
\sqrt{5}: 2 \sqrt{2}: 3
$$
(vi) $$
4 \Delta
$$
$$ \text { Then, the correct match is } $$
A
A-VI, B-I, C-II, D-III
B
A-II, B-I, C-V, D-III
C
A-II, B-VI, C-V, D-I
D
A-VI, B-II, C-I, D-IV
4
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Let $O(\mathbf{O}), A(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+\hat{\mathbf{k}}), B(-2 \hat{\mathbf{i}}+3 \hat{\mathbf{k}}), C(2 \hat{\mathbf{i}}+\hat{\mathbf{j}})$ and $D(4 \hat{\mathbf{k}})$ are position vectors of the points $O, A, B, C$ and $D$. If a line passing through $A$ and $B$ intersects the plane passing through $O, C$ and $D$ at the point $R$, then position vector of $R$ is
A
$-8 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}+7 \hat{\mathbf{k}}$
B
$2 \hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}$
C
$-7 \hat{\mathbf{i}}-6 \hat{\mathbf{j}}-5 \hat{\mathbf{k}}$
D
$3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-5 \hat{\mathbf{k}}$
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