1
AP EAPCET 2022 - 5th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic field in a plane electromagnetic wave is given as $$\mathbf{B}=\left(3 \times 10^{-7} \mathrm{~T}\right) \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{j}$$

The electric field of this wave is given as

A
$$90 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{i} \mathrm{~Vm}^{-1}$$
B
$$90 \sin \left(3 \times 10^4 \mathrm{x}+9 \times 10^{12} t\right) \hat{\mathrm{k}} \mathrm{~Vm}^{-1}$$
C
$$45 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{i} \mathrm{~Vm}^{-1}$$
D
$$45 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{k} \mathrm{~Vm}^{-1}$$
2
AP EAPCET 2022 - 5th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment the slits are 3 mm apart and are illuminated by light of two wavelengths $$3750 \mathop A\limits^o$$ and $$7500 \mathop A\limits^o$$. The screen is placed at 4 m from the slits. The minimum distance from the common central bright fringe on the screen at which the bright fringe of one interference pattern due to one wavelength coincide with the bright fringe of the other is

A
2 mm
B
3 mm
C
1 mm
D
8 mm
3
AP EAPCET 2022 - 5th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

The following statement is correct in the case of photoelectric effect

A
For a given frequency of incident radiation, the stopping potential varies linearly with its intensity.
B
For a given frequency of incident radiation, the photocurrent is independent of its intensity.
C
For a given frequency of a incident radiation, the maximum kinetic energy of the photoelectrons is independent of its intensity.
D
For a frequency lower than cutoff frequency, photoelectric emissions can occur if intensity of incident light is increased slightly.
4
AP EAPCET 2022 - 5th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

An electron in the hydrogen atom excites from 2nd orbit to 4th orbit then the change in angular momentum of the electron is (Planck's constant $$h=6.64 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$)

A
$$2.11 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
B
$$1.05 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
C
$$0.57 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
D
$$422 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
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