There are 10 points in a plane, out of these 6 are collinear. If $$N$$ is the total number of triangles formed by joining these points, then $$N=$$

205 students take an examination of whom 105 pass in English, 70 students pass in Mathematics and 30 students pass in both. How many students fail in both subjects?

In an examination, the maximum marks for each of three subjects is $$n$$ and that for the fourth subject is $$2 n$$. The number of ways in which candidates can get $$3 n$$ marks is

$$\frac{2 x^2+1}{x^3-1}=\frac{A}{x-1}+\frac{B x+C}{x^2+x+1} \Rightarrow 7 A+2 B+C=$$