To obtain dimension of $$61.18$$ $$mm$$ using slip gages, the most appropriate combination is

A shaft of diameter $${20^{\matrix{ { + 0.05} \cr { - 0.15} \cr } }}$$ and a hole of diameter $${20^{\matrix{ { + 0.20} \cr { + 0.10} \cr } }}\,\,mm$$ when assembled would yield.

$$A$$ $$30$$ $$mm$$ hole shaft assembly results in minimum and maximum clearances of $$0.03$$ $$mm$$ and $$0.30$$ $$mm$$ respectively. The hole has a unilateral tolerance with zero fundamental deviation. If the tolerance on the shaft is $$0.08$$ $$mm,$$ the maximum size of the hole is

In mass manufacturing, two holes in a plate type of component are ideally located with the help of