MHT CET (PCB) 2024 22th April Evening Shift | Gravitation Question 3 | Physics

The period of revolution of planet A around the sun is 8 times that of $B$. The distance of $A$ from the sun is how many times greater than that of $B$ from the sun?

MHT CET (PCB) 2024 22th April Evening Shift

MCQ (Single Correct Answer)

-0

A satellite of mass ' $m$ ' is orbiting the earth of radius ' $R$ ' at height ' $h$ ' from the surface of earth. The total energy of the satellite is ( $\mathrm{g}=$ acceleration due to gravity at the earth's surface)

$-\frac{\mathrm{mgR}^2}{2(\mathrm{R}+\mathrm{h})}$

$+\frac{m g R^2}{2(R+h)}$

$\frac{2 \mathrm{mgR}^2}{(\mathrm{R}+\mathrm{h})}$

$\quad-\frac{2 \mathrm{mgR}^2}{(\mathrm{R}+\mathrm{h})}$

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

A satellite is revolving round the earth with orbital speed ' $\mathrm{V}_0$ '. If it stops suddenly, the speed with which it will strike the surface of the earth would be ( $\mathrm{V}_{\mathrm{e}}=$ escape velocity of a particle on earth's surface)

$\frac{\mathrm{V}_{\mathrm{c}}^2}{\mathrm{~V}_0}$

$\quad 2 \mathrm{~V}_0$

$\sqrt{V_e^2-V_0^2}$

$\sqrt{\mathrm{V}_{\mathrm{e}}^2-2 \mathrm{~V}_0^2}$

MHT CET (PCB) 2024 22th April Morning Shift

MCQ (Single Correct Answer)

-0

The height at which the acceleration due to gravity becomes $\frac{g}{4}$ in terms of $R$ is $[R=$ the radius of the earth $]$

$\frac{R}{\sqrt{2}}$

$\sqrt{2} R$

$2 R$

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