1
MHT CET (PCB) 2024 22th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A hollow charged metal sphere has a radius ' $r$ '. If the potential difference between its surface and a point at a distance ' 3 r ' from the centre is ' $v$ ', then the electric field intensity at a distance ' $3 r$ ' is

A
$\frac{\mathrm{V}}{2 \mathrm{r}}$
B
$\frac{\mathrm{v}}{3 \mathrm{r}}$
C
$\frac{v}{6 r}$
D
$\frac{\mathrm{v}}{4 \mathrm{r}}$
2
MHT CET (PCB) 2024 22th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In the diagram, the total electric flux through the closed surface ' S ' is

[Given $\mathrm{q}=$ charge

$\varepsilon_0=$ permittivity of free space]

A
$\frac{q}{\varepsilon_0}$
B
$\frac{-2 q}{\varepsilon_0}$
C
$\frac{-q}{\varepsilon_0}$
D
$\frac{3 q}{\varepsilon_0}$
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