Simple Harmonic Motion · Physics · MHT CET (Biology)
MCQ (Single Correct Answer)
A particle of mass 0.02 kg executes S.H.M. about $\mathrm{x}=0$ under the influence of a force as shown in figure. The period of S.H.M. is
Two (A and B) pendulums begin to swing simultaneously. The first pendulum (A) makes five oscillations when the other (B) makes three oscillations. The ratio of the lengths of pendulum $A$ to that of $B$ is
A particle performs S.H.M. with amplitude 'A'. The speed of the particle is $\left(\frac{1}{3}\right)^{\text {rd }}$ of the maximum speed when its displacement from the mean position is
A particle vibrating simple harmonically has an acceleration of $16 \mathrm{~cm} / \mathrm{s}^2$, when it is at a distance of 4 cm from the mean position. Its periodic time is
The average velocity of a particle performing S.H.M. in one complete vibration is ( $\mathrm{A}=$ amplitude of S.H.M., $\omega=$ angular velocity)
A mass ' $M$ ' is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes S.H.M. of periodic time ' $T$ '. If the mass is increased by ' $m$ ', the time period becomes $4 T / 3$, then the ratio of $\frac{\mathrm{M}}{\mathrm{m}}$ is
A particle starts from mean position and performs S.H.M. with period 6 second. At what time its kinetic energy is $50 \%$ of total energy?
$$ \left(\cos 45^{\circ}=\frac{1}{\sqrt{2}}\right) $$
A particle of mass ' m ' is executing S.H.M. about the origin on $x$-axis with frequency $\sqrt{\frac{\mathrm{ka}}{\pi \mathrm{m}}}$, where ' $k$ ' is a constant and ' $a$ ' is the amplitude of S.H.M. If ' x ' is a displacement of a particle, at time ' $t$ ', potential energy of the particle will be
A pendulum is performing simple harmonic motion. The acceleration of the bob is $20 \mathrm{~cm} \mathrm{~s}^{-2}$ at a distance of 5 cm from mean position. The time period of oscillation is
Two particles execute S.H.M. of same amplitude and frequency along the same straight line path. They pass each other when going in opposite directions, each time their displacement is half the amplitude. The phase difference between them is $\left(\sin 30^{\circ}=0 \cdot 5\right)$