Fluid Mechanics · Physics · MHT CET (Biology)

When a big drop of water is formed from n small drops of water, the energy loss is 4 E , where E is the energy of the bigger drop. If $R$ and $r$ is the radius of the bigger and the smaller drop respectively then number of smaller drops $n$ is

Two solid spheres of same material but of mass ' M ' and ' 8 M ' fall simultaneously through a viscous liquid. Their terminal velocities are respectively ' V ' and ' nV '. The value ' n ' is

A small steel ball of mass ' M ', radius ' R ' and density ' $\rho$ ' falls with terminal velocity through a tube filled with glycerine of density ' $\sigma$ '. The viscous force acting on the steel ball is ( $\mathrm{g}=$ acceleration due to gravity)

If the shape of the liquid surface is curved, then the

A spherical liquid drop of radius R is divided into 64 equal droplets. If surface tension is $T$ then the work done in this process will be

A glass capillary of radius 0.35 mm is inclined at $60^{\circ}$ with the vertical in water. The length of water column in the capillary tube is (surface tension of water $=7 \times 10^{-2} \mathrm{Nm}^{-1}$, acceleration due to gravity $=10 \mathrm{~m} / \mathrm{s}^2, \cos 0^{\circ}=1$, $\cos 60^{\circ}=0.5$, density of water $=1 \mathrm{gram} / \mathrm{cm}^3$ )

At two points on a horizontal tube of varying cross-section the radii are 1 cm and $\mathbf{0 . 4 ~ c m}$, velocities of fluid are $\mathrm{V}_1, \mathrm{~V}_2$ and pressure difference ( $P_1-P_2$ ) between these points is 4.9 cm of water. The value of $\sqrt{V_2^2-V_1^2}$ is ( $\mathrm{g}=$ acceleration due to gravity $\mathrm{g}=980 \mathrm{~cm} / \mathrm{s}^2$ )

Water rises up to height ' $x$ ' in a capillary tube immersed vertically in water. When the whole arrangement is taken to a depth 'd' in a mine, the water level rises height ' $Y$ '. If ' $R$ ' is the radius of earth then the ratio $(\mathrm{Y} / \mathrm{x})$ is

Water is flowing through a horizontal pipe in a streamline flow. At the narrowest part of the pipe

Work done to get ' $n$ ' spherical drops of equal size from a single spherical drop of water, is proportional to

A light metal disc of radius ' $r$ ' floats on water surface and bends the surface downwards along the perimeter making an angle ' $\theta$ ' with the vertical edge of the disc. If the weight of water displaced by the disc is ' W ', the weight of the metal disc is [ $\mathrm{T}=$ surface tension of water]