1
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In the spectrum of hydrogen atom the ratio of the longest wavelength in the Balmer series to the longest wavelength in the Lyman series is

A

$\frac{9}{4}$

B

$\frac{4}{9}$

C

$\frac{27}{5}$

D

$\frac{5}{27}$

2
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

The series limit for the frequency of Balmer series is ' $\mathrm{v}_{\mathrm{B}}$ ', then the series limit frequency of Paschen series ' $v_p$ ' is

A

$\quad \frac{2}{9} \mathrm{v}_{\mathrm{B}}$

B

$\quad \frac{9}{4} \mathrm{v}_{\mathrm{B}}$

C

$\frac{4}{9} \mathrm{v}_{\mathrm{B}}$

D

$\frac{2}{3} \mathrm{~V}_{\mathrm{B}}$

3
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Radioactive materials A and B have decay constants ' $9 \lambda$ ' and ' $\lambda$ ' respectively. Initially they have same number of nuclei. The ratio of number of nuclei of material ' $A$ ' to that of ' $B$ ' will be $\left(\frac{1}{\mathrm{e}}\right)$ after time ' $t$ '. So ' $t$ ' is equal to

A
$\frac{1}{\lambda}$
B
$\frac{1}{6 \lambda}$
C
$\frac{1}{8 \lambda}$
D
$\frac{1}{9 \lambda}$
4
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $R_1$ and $R_2$ are the radii of the atomic nuclei of mass numbers 27 and 125 respectively, then the ratio $R_2: R_1$ is

A
$\frac{125}{27}$
B
$\sqrt{\frac{125}{27}}$
C
$\frac{5}{3}$
D
$\frac{3}{5}$

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