MHT CET (PCB) 2025 9th April Evening Shift | Vector Algebra Question 1 | Physics

At what angle should the two forces $2 \overrightarrow{\mathrm{P}}$ and $\sqrt{2} \overrightarrow{\mathrm{P}}$ act so that the resultant force is $\sqrt{10} \overrightarrow{\mathrm{P}}$ ?

$\cos ^{-1}\left(\frac{1}{\sqrt{2}}\right)$

$\cos ^{-1}\left(\frac{1}{2}\right)$

$\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)$

$\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)$

MHT CET (PCB) 2025 9th April Morning Shift

MCQ (Single Correct Answer)

-0

If $|\vec{A} \times \vec{B}|=\sqrt{3}(\vec{A} \cdot \vec{B})$ then the value of $|\vec{A}+\vec{B}|$ is $\left(\tan 60^{\circ}=\sqrt{3}, \cos 60^{\circ}=0.5\right)$

$\left(A^2+B^2+\frac{A B}{\sqrt{3}}\right)^{\frac{1}{2}}$

$\left(A^2+B^2+A B\right)^{\frac{1}{2}}$

$\left(A^2+B^2+\sqrt{3} A B\right)^{\frac{1}{2}}$

$\mathrm{A}+\mathrm{B}$

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