1
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum has mass 2 gram and charge $2 \mu \mathrm{C}$. In a uniform horizontal electric field of intensity $1000 \mathrm{~V} / \mathrm{m}$, pendulum is at rest. At equilibrium, the angle made by the pendulum with the vertical is ( $\mathrm{g}=$ acceleration due to gravity $=10 \mathrm{~m} / \mathrm{s}^2$ )

A

$\tan ^{-1}(0.2)$

B

$\tan ^{-1}(0.1)$

C

$\tan ^{-1}(0.4)$

D

$\tan ^{-1}(0.5)$

2
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

The charges are arranged at the four corners of square $A B C D$ of side ' $d$ ' as shown in figure. The work required to put this arrangement together is given by

MHT CET (PCB) 2025 9th April Morning Shift Physics - Electrostatics Question 2 English
A

$\frac{-9 q^2}{4 \pi \varepsilon_0 d}$

B

$\frac{-7 q^2}{4 \pi \varepsilon_0 d}$

C

$\frac{-q^2}{4 \pi \varepsilon_0 d}[9-2 \sqrt{2}]$

D

$\frac{-q^2}{4 \pi \varepsilon_0 d}[9+2 \sqrt{2}]$

3
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Three charges $Q,-2 q$ and $-2 q$ are placed at the vertices of an isosceles right-angled triangle as shown in figure. The net electrostatic potential energy is zero if $Q$ is equal to

MHT CET (PCB) 2024 22th April Evening Shift Physics - Electrostatics Question 6 English

A
$\frac{\mathrm{q}}{2}$
B
$\sqrt{2} q$
C
$\frac{q}{\sqrt{2}}$
D
$\frac{q}{2 \sqrt{2}}$
4
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A large insulated sphere of radius ' $r$ ', charged with ' $Q$ ' units of electricity, is placed in contact with a small insulated uncharged sphere of radius ' R ' and is then separated. The charge on the smaller sphere will now be

A
$\mathrm{Q}(\mathrm{r}+\mathrm{R})$
B
$\mathrm{Q}(\mathrm{r}-\mathrm{R})$
C
$\frac{Q}{r+R}$
D
$\frac{\mathrm{QR}}{\mathrm{R}+\mathrm{r}}$

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