1
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

' n ' polarising sheets are arranged such that each makes an angle $45^{\circ}$ with the proceeding sheet. An unpolarised light of intensity I is incident into this arrangement. The output intensity is I/ 64 . The value of $n$ will be $\left(\cos 45^{\circ}=1 / \sqrt{2}\right)$

A

6

B

5

C

4

D

8

2
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In an interference experiment, the phase difference between the waves reaching a first dark point is

A

zero

B

$\pi^{\mathrm{c}}$

C

$\left(\frac{3 \pi}{2}\right)^{\mathrm{c}}$

D

$(2 \pi)^c$

3
MHT CET (PCB) 2025 9th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, the intensities at two points, for the path difference $\frac{\lambda}{4}$ and $\frac{\lambda}{3}$ are $\mathrm{I}_1$ and $\mathrm{I}_2$ respectively. If $\mathrm{I}_0$ denotes the intensity produced by each one of the individual slits then the ratio $\left(\mathrm{I}_1+\mathrm{I}_2\right): \mathrm{I}_0$ is $\left(\cos 45^{\circ}=1 / \sqrt{2}\right)\left(\cos 60^{\circ}=0.5\right)$

A

2

B

3

C

4

D

1

4
MHT CET (PCB) 2024 22th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, fringe width is 1.4 mm with light of wavelength $6000 $$\mathop {\rm{A}}\limits^{\rm{o}} $. If the light of wavelength $5400 $$\mathop {\rm{A}}\limits^{\rm{o}} $ is used, with no other change in the experimental set up. The change in fringe width is

A
1.26 mm
B
0.12 mm
C
0.13 mm
D
0.14 mm

MHT CET (Biology) Subjects

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