What is the equation of the straight line which is perpendicular to y = x and passes through (3, 2) ?

The straight lines x + y $$-$$ 4 = 0, 3x + y $$-$$ 4 = 0 and x + 3y $$-$$ 4 = 0 form a triangle, which is

Under what condition will the lines $m{}^{2}x+ny-1=0$ and $n{}^{2}x-my+2=0$ be perpendicular?

If p and q are real numbers between 0 and 1 such that the points (p,1), (1,q) and (0,0) form an equilateral triangle, then what is $(p+q)$ equal to?