If $$\left| {z - {4 \over z}} \right| = 2$$, then the maximum value of $$\left| z \right|$$ is equal to

Geometrically $${\mathop{\rm Re}\nolimits} ({z^2} - i) = 2$$, where, $$i = \sqrt { - 1} $$ and Re is the real part, represents

The value of $${i^{2n}} + {i^{2n + 1}} + {i^{2n + 2}} + {i^{2n + 3}}$$, where $$i = \sqrt { - 1} $$, is

The value of $${\left( {{{ - 1 + i\sqrt 3 } \over 2}} \right)^n} + {\left( {{{ - 1 - i\sqrt 3 } \over 2}} \right)^n}$$, where n is not a multiple of 3 and $$i = \sqrt { - 1} $$, is