If $$f(x) = {x \over {x - 1}}$$, then what is $${{f(a)} \over {f(a + 1)}}$$ equal to ?

Let f : [$$-$$6, 6] $$\to$$ R be defined by f(x) = x² $$-$$ 3. Considered the following :

1. $$(f \circ f \circ f)( - 1) = (f \circ f \circ f)(1)$$

2. $$(f \circ f \circ f)( - 1) - 4(f \circ f \circ f)(1)$$

$$ = (f \circ f)(0)$$

Which of the above is/are correct?

Let f(x) = px + q and g(x) = mx + n. Then, f(g(x)) = g(f(x)) is equivalent to

Which one of the following functions is neither even nor odd?