1
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
A function is defined as follows

$$f(x) = \left\{ {\matrix{ { - {x \over {\sqrt {{x^2}} }},} & {x \ne 0} \cr {0,} & {x = 0} \cr } } \right.$$

Which one of the following is correct in respect of the above function?
A
f(x) is continuous at x = 0 but not differentiable at x = 0
B
f(x) is continuous as well as differentiable at x = 0
C
f(x) is discontinuous at x = 0
D
None of the above
2
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
Consider the following statements

1. $$x + {x^2}$$ is continuous at x = 0

2. $$x + \cos {1 \over x}$$ is discontinuous at x = 0

3. $${x^2} + \cos {1 \over x}$$ is continuous at x = 0

Which of the above are correct?
A
1 and 2 only
B
2 and 3 only
C
1 and 3 only
D
1, 2 and 3
3
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
A function is defined in (0, $$\infty$$) by

$$f(x) = \left( {\matrix{ {1 - {x^2}} & {for} & {0 < x \le 1} \cr {\ln x} & {for} & {1 < x \le 2} \cr {\ln 2 - 1 + 0.5x} & {for} & {2 < x < \infty } \cr } } \right.$$

Which one of the following is correct in respect of the derivative of the function, i.e., f'(x) ?
A
f'(x) = 2x for 0 < x $$\le$$ 1
B
f'(x) = $$-$$ 2x for 0 < x $$\le$$ 1
C
f'(x) = $$-$$2x for 0 < x < 1
D
f'(x) = 0 for 0 < x < $$\infty$$
4
NDA 2017 Paper 2
MCQ (Single Correct Answer)
+2.5
-0.83
If $$\mathop {\lim }\limits_{x \to {\pi \over 2}} {{\sin x} \over x} = l$$ and $$\mathop {\lim }\limits_{x \to \infty } {{\cos x} \over x} = m$$, then which one of the following is correct?
A
l = 1, m = 1
B
l = $${2 \over \pi }$$, m = $$\infty$$
C
l = $${2 \over \pi }$$, m = 0
D
l = 1, m = $$\infty$$
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