1
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
If $ x \sqrt{1+y}+y \sqrt{1+x}=0 $, then $ \frac{d y}{d x}= $
A
$ \frac{x+1}{x} $
B
$ \frac{1}{1+x} $
C
$ \frac{-1}{(1+x)^{2}} $
D
$ \frac{x}{1+x} $
2
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
Consider the function $ f(x)=\frac{|x-1|}{x^{2}} $, then $ f(x) $ is
A
increasing in $ (0,1) \cup(2, \infty) $
B
increasing in $ (-\infty, 0) \cup(0,1) $
C
decreasing in $ (-\infty, 0) \cup(2, \infty) $
D
decreasing in $ (0,1) \cup(2, \infty) $
3
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
There are four numbers of which the first three are in GP and the last three are in AP, whose common difference is 6 . If the first and the last numbers are equal, then two other numbers are
A
$ -2,4 $
B
$ -4,2 $
C
2,6
D
None of the above
4
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
$ \int_{0}^{\infty} \frac{d x}{\left(x^{2}+a^{2}\right)\left(x^{2}+b^{2}\right)} $ is
A
$ \frac{\pi a b}{a+b} $
B
$ \frac{a b}{2(a+b)} $
C
$ \frac{\pi}{2 a b(a+b)} $
D
$ \frac{\pi(a+b)}{2 a b} $
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