1
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
There are four numbers of which the first three are in GP and the last three are in AP, whose common difference is 6 . If the first and the last numbers are equal, then two other numbers are
A
$ -2,4 $
B
$ -4,2 $
C
2,6
D
None of the above
2
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
$ \int_{0}^{\infty} \frac{d x}{\left(x^{2}+a^{2}\right)\left(x^{2}+b^{2}\right)} $ is
A
$ \frac{\pi a b}{a+b} $
B
$ \frac{a b}{2(a+b)} $
C
$ \frac{\pi}{2 a b(a+b)} $
D
$ \frac{\pi(a+b)}{2 a b} $
3
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
The line $ y=m x $ bisects the area unclosed by lines $ x=0, y=0 $ and $ x=\frac{3}{2} $ and the curve $ y=1+4 x-x^{2} $. Then, the value of $ m $ is
A
$ \frac{13}{6} $
B
$ \frac{13}{2} $
C
$ \frac{13}{5} $
D
$ \frac{13}{7} $
4
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1

The solution of the differential equation

$ (x+1) \frac{d y}{d x}-y=e^{3 x}(x+1)^{2} $ is

A
$ y=(x+1) e^{3 x}+C $
B
$ 3 y=(x+1)+e^{3 x}+C $
C
$ \frac{3 y}{x+1}=e^{3 x}+C $
D
$ y e^{-3 x}=3(x+1)+C $
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