1
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
A projectile is projected with velocity of $ 40 \mathrm{~m} / \mathrm{s} $ at an angle $ \theta $ with the horizontal. If $ R $ be the horizontal range covered by the projectile and after $ t $ seconds, its inclination with horizontal becomes zero, then the value of $ \cot \theta $ is [Take, $ g=10 \mathrm{~m} / \mathrm{s}^{2} $ ]
A
$ \frac{R}{20 t^{2}} $
B
$ \frac{R}{10 t^{2}} $
C
$ \frac{5 R}{t^{2}} $
D
$ \frac{R}{t^{2}} $
2
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
A dust particle of mass $ 4 \times 10^{-12} \mathrm{mg} $ in suspended in air under the influence of an electric field of $ 50 \mathrm{~N} / \mathrm{C} $ directed vertically upwards. How many electrons were removed from the neutral dust particle? [Take, $ g=10 \mathrm{~m} / \mathrm{s} $ $ { }^{2} $ ]
A
15
B
8
C
5
D
4
3
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
An ideal massless spring $ S $ can be compressed 1 m by a force of 100 N in equilibrium. The same spring is placed at the bottom of a frictionless inclined plane inclined at $ 30^{\circ} $ to the horizontal. A 10 kg block $ M $ is released from rest at the top of the incline and is brought to rest momentarily after compressing the spring by 2 m . If $ g=10 \mathrm{~m} / \mathrm{s}^{2} $, what is the speed of mass just before it touches the spring?

BITSAT 2024 Physics - Work, Energy and Power Question 1 English

A
$ \sqrt{20} \mathrm{~m} / \mathrm{s} $
B
$ \sqrt{30} \mathrm{~m} / \mathrm{s} $
C
$ \sqrt{10} \mathrm{~m} / \mathrm{s} $
D
$ \sqrt{40} \mathrm{~m} / \mathrm{s} $
4
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
You measure two quantities as $ A=1.0 \mathrm{~m} \pm 0.2 \mathrm{~m} $, $ B=2.0 . \mathrm{m} \pm 0.2 \mathrm{~m} $. We should report correct value for $ \sqrt{A B} $ as
A
$ 1.4 \mathrm{~m} \pm 0.4 \mathrm{~m} $
B
$ 1.41 \mathrm{~m} \pm 0.15 \mathrm{~m} $
C
$ 1.4 \mathrm{~m} \pm 0.3 \mathrm{~m} $
D
$ 1.4 \mathrm{~m} \pm 0.2 \mathrm{~m} $
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