1
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
Let $ \mathbf{a}=\hat{\mathbf{i}}-\hat{\mathbf{k}}, \mathbf{b}=x \hat{\mathbf{i}}+\hat{\mathbf{j}}+(1-x) \hat{\mathbf{k}} $ and $ \mathbf{c}=y \hat{\mathbf{i}}+x \hat{\mathbf{j}}+(1+x-y) \hat{\mathbf{k}} $. Then, $ [\mathbf{a} \mathbf{b} \mathbf{c}] $ depends on
A
only $ y $
B
only $ x $
C
both $ x $ and $ y $
D
neither $ x $ nor $ y $
2
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
The magnitude of projection of line joining ( 3,4 , $ 5) $ and $ (4,6,3) $ on the line joining $ (-1,2,4) $ and $ (1,0,5) $ is
A
$ \frac{4}{3} $
B
$ \frac{2}{3} $
C
$ \frac{8}{3} $
D
$ \frac{1}{3} $
3
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
The Boolean expression $ \sim(p \vee q) \vee(\sim p \wedge q) $ is equivalent to
A
$ p $
B
$ \sim q $
C
$ q $
D
$ \sim p $
4
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
If $ \sum\limits_{k=1}^{n} k(k+1)(k-1)=p n^{4}+q n^{3}+t n^{2}+s n $, where $ p, q, t $ and $ s $ are constants, then the value of $ s $ is equal to
A
$ -\frac{1}{4} $
B
$ -\frac{1}{2} $
C
$ \frac{1}{2} $
D
$ \frac{1}{4} $
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