1
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

The area of one curvilinear triangle formed by curves y = sin x, y = cos x and X-axis, is

A
2 sq units
B
(2 + $$\sqrt2$$) sq units
C
(2 $$-$$ $$\sqrt2$$) sq units
D
None of these
2
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

Solution of $$\left( {{{x + y - 1} \over {x + y - 2}}} \right){{dy} \over {dx}} = \left( {{{x + y + 1} \over {x + y + 2}}} \right)$$, given that y = 1 when x = 1 is

A
$$\ln \left| {{{{{(x - y)}^2} - 2} \over 2}} \right| = 2(x + y)$$
B
$$\ln \left| {{{{{(x + y)}^2} - 2} \over 2}} \right| = 2(x - y)$$
C
$$\ln \left| {{{{{(x - y)}^2} + 2} \over 2}} \right| = 2(x + y)$$
D
$$\ln \left| {{{{{(x + y)}^2} + 2} \over 2}} \right| = 2(x + y)$$
3
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

If $$y = \sin \left( {2{{\tan }^{ - 1}}\sqrt {{{1 - x} \over {1 + x}}} } \right)$$, then $${{dy} \over {dx}}$$ is :

A
1
B
$$-$$1
C
$${x \over {\sqrt {{x^2} - 1} }}$$
D
$${{ - x} \over {\sqrt {1 - {x^2}} }}$$
4
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

The maximum value of the function y = x(x $$-$$ 1)2, is

A
0
B
$${4 \over {27}}$$
C
$$-$$4
D
None of these
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12